Question

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(c9p42) A piece of metal is pressed against the rim of a 2.4- kg, 18- cm-diameter grinding wheel that is turning at 2800 rpm. The metal has a coefficient of friction of 0.75 with respect to the wheel. When the motor is cut off, with how much force must you press to stop the wheel in 20.0 s? 4.6N Submit Answer Incorrect. Tries 1/10 Previous Tries

Answer 1

Given data; Mass 22:4kg time = 20 sec, Diametes = 180m coeflicient of Biction 1075 W7 2800 rpro conuest nto rad's) = 2800 year) := 293-06 Yadls let us consideri UFR = IW . (1 22 m) 0.75XFX (0:09), 20158214 (0.0932 x 293,06 0,0675XF = 0.142u F22:4N).