Given:
ΔHo rxn = 202.8 KJ/mol
Hof(H2(g)) = 0.0 KJ/mol
Hof(Fe(s)) = 0.0 KJ/mol
Hof(H2O(g)) = -241.818 KJ/mol
Balanced chemical equation is:
Fe3O4(s) + 4 H2(g) ---> 3 Fe(s) + 4 H2O(g)
ΔHo rxn = 3*Hof(Fe(s)) + 4*Hof(H2O(g)) - 1*Hof( Fe3O4(s)) - 4*Hof(H2(g))
202.8 = 3*(0.0) + 4*(-241.818) - 1*Hof(Fe3O4(s)) - 4*(0.0)
Hof(Fe3O4(s)) = -1170.072 KJ/mol
Answer: -1170.07 KJ/mol
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