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Calculate either HOor OH for each of the solutions at 25 °C. Solution A: [OH 2.99 x 10- M Solution A: [H,O]- Solution B: [H,O

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Conc [OH-] = 2.99E-07 lonic product of water Kw = [H3O+] [OH-] 1.0 x 10^-14 or Then (H3O+] = 1.0 x 10^-14 / (OH-] = 1.0 x 10^

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