Question

4. A student prepared a set of solutions using the serial dilution method. The stock solution had a concentration of 15 drops/L. The solutions were prepared according the following procedure. Calculation the concentrations of solutions A-D. Show the calculation for each solution, complete with equations, units, and the correct number of significant figures. Pay attention to units! Solution A: 50.0 mL Stock Solution and 50.0 mL deionized water Solution B: 50.0 mL Solution A and 50.0 mL deionized water Solution C: 50.0 mL Solution B and 50.0 mL deionized water Solution D: 50.0 mL Solution C and 50.0 mL deionized water

Please explain how to go from 15 drops/L to 15 drops/mL. And show all work and show how the final answer has to be in drops/mL thank you

Answer 1

Stock t so ml sola Et sond H2O t some 8 of " B Tho (sond) som stocksd" tsomo San concentra scoop/ bitre = 150 mp | 100omp = 158103 drop/ml concentration a drops Volume looml wa me A Total drops in some Stocksal" _ 15x10h doop x50ml = 750 103 drops. final volume of A = soud stock +sound water = looml. concentration = 750x103 drops concentration 100 ml 27.5X163 drops Total doop in 5ond of Totaldrops in some Sol" A = 7.5x108 days of solm B = = 7.5x153x50 cooler 7.5 x 10 doby soul final volume = 100ml - 715x10 3 x 50 drops concentration of Final volume = 100g solution B = 7.5 X1 & Sodos concentraction of = 7:5 x103 drops solutione sond sale at 7.58 103 x 56 drops som H2O ca - me S Tood sob D Total drops in solation so ml of sal" c = concentration x soud (D) = 7.7 x 16 3 drops xsone = 7.5 x 10-3 x 50 drops final voleeme = 100 ml Į 100 my = 7.5 x 103 drops - 9.375 x10 h das ration of solno = drops = 7.5x10 3x so drops - volume N

To make 15drope (me solution from is doops/L 15 drops - 15 drope 15000 doops ml ool lit . (ind = 100h) Addition of extra (15000-15) drops to IL stock sola = 14905 so that in ont let it become 15000 drops