Question

please explain #8 and #9. show all work. thank you

8. An antifreeze solution is prepared by adding 50.0 mL of ethylene glycol, C2H602 (density = 1.12 g/mL) to 50.0 g of water. Calculate the freezing point of this solution. 9. Which has the highest boiling point? (all solutions are in the same solvent) 1.0 M Co(NO3)2 2.0 M KCI 0.5 M C2H4O2

Answer 1

- AND-8 final freezing Point - Initial foreezing point + change in freezing Point0) I 0 o is dissociation) association factor kf= 1086 oc/m. ma molality = no of moles of solule mass of solventing) no of moles of solute mass of Givensolute Моя мор mass of liven colute density & Volume = 112+50=56gn molar Mass of one O₂ = 2x12+ 6+1+2016 - 56gm . » No. of moles= 56/6=2 Molality = Votso - dom. Alfix kg om 2 • 3 lad for organic compounds dissolned in water! = -1.86 x 1 x 20 = -37.2°C : freezing point of this colution will be = 0.00+ (-37.2°C)=1.

I they @ L.OM Collo) @ 209 kel ②. 0.5 MCGHEO2 A Hi***m. Atoa Pak by m. kho is same for all the solution because solvent is common i is higher for ionic compound in water than covalent compound which is greater than organic compound ickel > icco(Noza) si (CH6O2). in for kel> Co criable> C2H602 . AT6 for kel> Co (NO) Cz M602 Tiginal porting point) = Tinitialt ATD. Tinitaal is same for all solution ol - др1 , 1. 209 kd has highest boiling point