Question

A solution of antifreeze is prepared by mixing 21.0mL of ethylene glycol (d = 1.11 g/mL; molar mass = 62.07 g/mol) with 50.0 mL H₂O (d = 1.00 g/mL) at 25°C. If the density of the antifreeze solution is 1.07 g/mL, what is its molarity (M)?

Answer 1

Given dadla, 21.0 mL or ethylene glycou os (dengesy : 1641 9/m2 meded With 50.0 mL H2O have'ng densely: 1:00 91ml) ou 25c . - our Fensul moddo is to find out the mass of the given Sounite and solvend we know, la mass I Volume / for ethylene guscal, m = (1.21*9/mL) x ( o for ethylene glycol, m= 23.31 m) gm. For H₂O m (50.0 mL) x ( 1.00 g/mL) - 50.0 gm Now the do sal mass = 23.31 + 50.0) gm = 73.31 gm. Then, we have the density of ansifreezing soun: 1.079/mL. NOW TO JOU Volume mars 73.31 - 1.07 6851 ml Density mojar ddy cai mass of the Solude x 1000 23.31 4 1000 62.09 x 68.51 moleccwart wedghd x volume of Salute - 5.48 mall din