An solution of antifreeze is prepared by mixing 21.0mL of ethylene glycol (d = 1.11 g/mL; molar mass = 62.07 g/mol) with...
An solution of antifreeze is prepared by mixing 21.0mL of ethylene glycol (d = 1.11 g/mL; molar mass = 62.07 g/mol) with 50.0 mL H2O (d = 1.00 g/mL) at 25°C. If the density of the antifreeze solution is 1.07 g/mL, what is its molarity?
Homework Answers
the solution requires the simple calculation and molarity formula whixh is done in the pictorial solution below:
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An solution of antifreeze is prepared by mixing 21.0mL of ethylene glycol (d = 1.11 g/mL; molar mass = 62.07 g/mol) with...
A solution of antifreeze is prepared by mixing 21.0mL of ethylene glycol (d = 1.11 g/mL;...
A solution of antifreeze is prepared by mixing 21.0mL of ethylene glycol (d = 1.11 g/mL; molar mass = 62.07 g/mol) with 50.0 mL H2O (d = 1.00 g/mL) at 25°C. If the density of the antifreeze solution is 1.07 g/mL, what is its molarity (M)?
A solution of antifreese is prepared by mixting 34.0mL of ethylene glycol (d=1.11g/mL; molar mass =62.07...
A solution of antifreese is prepared by mixting 34.0mL of ethylene glycol (d=1.11g/mL; molar mass =62.07 g/mol) with 50.0 mL H20 (d=1.00 g/mol) at 25 degrees celsius. if the density of the antifreeze solution is 1.07 g/ mL, what is the molarity?
An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d=1.114 g/mL;M=62.07 g/mol)...
An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d=1.114 g/mL;M=62.07 g/mol) and water (d=1.00 g/mL) at 20°C. The density of the mixture is 1.070 g/mL. Express the concentration of ethylene glycol as (a) volume percent 50v/v (b) mass percent 52.05w/w (c) molarity 0.0089 (d) molality 0.0083 (e) mole fraction
An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d=1.114 g/mL; M=...
An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d=1.114 g/mL; M= 62.07 g/mol) and water (d=1.00 g/mL) at 20°C. The density of the mixture is 1.070 g/mL. Express the concentration of ethylene glycol as (a) volume percent I % v/v (b) mass percent % w/w (c) molarity м (d) molality (e) mole fraction
Please explain. Thank you. (8) An antifreeze solution is prepared by mixing 719 mL of ethyl-...
Please explain. Thank you.
(8) An antifreeze solution is prepared by mixing 719 mL of ethyl- ene glycol (C2H4O2(1), M = 62.07 g/mol, d = 1.11 g/mL, struc- H-0-ċ-ċ-0-H ture shown at right) and 200 mL of water (H2O(1), M = HH 18.02 g/mol, d = 1.00 g/mL). The density of the resulting anti- freeze solution is equal to 1.10 g/mL. (a) [8 points] Calculate the volume of antifreeze solution prepared. (Hint: The volume of antifreeze solution is NOT equal...
Ethylene glycol is used in automobile radiators as an antifreeze. Use the following information to determine the freezi...
Ethylene glycol is used in automobile radiators as an antifreeze. Use the following information to determine the freezing point of an antifreeze solution made by mixing 2.5 L of ethylene glycol with 2.5 L of water. Ethylene glycol is essentially nonvolatile and it does not dissociate in water. Molar mass of ethylene glycol = 62.1 g/mol; density of ethylene glycol = 1.11 g/mL; density of water = 1.00 g/mL; Kf for water = 1.86 degrees Celsius kg/mol
Calculate the mass of ethylene glycol (C2H6O2 - molar mass =62.07 g/mol) that must be added...
Calculate the mass of ethylene glycol (C2H6O2 - molar mass =62.07 g/mol) that must be added to 1.00 kg of ethanol (C2H5OH- molar mass =46.07 g/mol) to reduce its vapor pressure by 10.0 torr at 35 degree C. The vapor pressure of pur ethanol at 35 degree C is 100 torr.
You have a 4M aqueous solution of ethylene glycol (62 g / mol molar mass). You...
You have a 4M aqueous solution of ethylene glycol (62 g / mol molar mass). You want to recover 49 ml of pure ethylene glycol from this solution. What is the minimum amount of aqueous solution required to obtain the desired ethylene glycol. density of ethylene glycol is 1.11 g / ml
Be sure to answer all parts. An automobile antifreeze mixture is made by mixing equal volumes...
Be sure to answer all parts. An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d - 1.114 g/mL; M-62.07 g/mol) and water (d = 1.00 g/mL) at 20°C. The density of the mixture is! 1.070 g/mL. Express the concentration of ethylene glycol as (a) volume percent %v/v (b) mass percent % w/w (c) molarity d) malality (b) mass percent (e) molarity (d) molality (e) mole fraction
1. Ethylene glycol, formula C2H602, is used as antifreeze for automobiles and is sometimes mixed with...
1. Ethylene glycol, formula C2H602, is used as antifreeze for automobiles and is sometimes mixed with water at a 1:1 ratio by volume and produces a solution with a density of 1.07 g/mbu Assume that the solution behaves ideally. Notes: at 25 °C the densities of water and ethylene glycol are 1.00 g/mL and 1.11 g/mL, respectively, the vapor pressures of water and ethylene glycol at 20 Care 17.54 torr and 0.06 torr, respectively, and Ky and K of water...
An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d=1.114 g/mL;M=62.07 g/mol) and water (d=1.00 g/mL) at 20°C. The density of the mixture is 1.070 g/mL. Express the concentration of ethylene glycol as (a) volume percent 50v/v (b) mass percent 52.05w/w (c) molarity 0.0089 (d) molality 0.0083 (e) mole fraction
An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d=1.114 g/mL; M= 62.07 g/mol) and water (d=1.00 g/mL) at 20°C. The density of the mixture is 1.070 g/mL. Express the concentration of ethylene glycol as (a) volume percent I % v/v (b) mass percent % w/w (c) molarity м (d) molality (e) mole fraction
Please explain. Thank you.
(8) An antifreeze solution is prepared by mixing 719 mL of ethyl- ene glycol (C2H4O2(1), M = 62.07 g/mol, d = 1.11 g/mL, struc- H-0-ċ-ċ-0-H ture shown at right) and 200 mL of water (H2O(1), M = HH 18.02 g/mol, d = 1.00 g/mL). The density of the resulting anti- freeze solution is equal to 1.10 g/mL. (a) [8 points] Calculate the volume of antifreeze solution prepared. (Hint: The volume of antifreeze solution is NOT equal...
Be sure to answer all parts. An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d - 1.114 g/mL; M-62.07 g/mol) and water (d = 1.00 g/mL) at 20°C. The density of the mixture is! 1.070 g/mL. Express the concentration of ethylene glycol as (a) volume percent %v/v (b) mass percent % w/w (c) molarity d) malality (b) mass percent (e) molarity (d) molality (e) mole fraction
1. Ethylene glycol, formula C2H602, is used as antifreeze for automobiles and is sometimes mixed with water at a 1:1 ratio by volume and produces a solution with a density of 1.07 g/mbu Assume that the solution behaves ideally. Notes: at 25 °C the densities of water and ethylene glycol are 1.00 g/mL and 1.11 g/mL, respectively, the vapor pressures of water and ethylene glycol at 20 Care 17.54 torr and 0.06 torr, respectively, and Ky and K of water...
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