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You have a 4M aqueous solution of ethylene glycol (62 g / mol molar mass). You...

You have a 4M aqueous solution of ethylene glycol (62 g / mol molar mass). You want to recover 49 ml of pure ethylene glycol from this solution. What is the minimum amount of aqueous solution required to obtain the desired ethylene glycol. density of ethylene glycol is 1.11 g / ml

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Answer #1

Volume of Ethylene glycal required = 49mL mass = Volume x density = (49x110g = 59.39g Males = 54.39 -0.877 mole 62 9 MalarityVolume of =) 0871 Aqueous solution -0.22L OmL

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