Solution:
1) The vapor pressure of solvent is related to the mole fraction of the solvent and its pure vapor pressure:
vapor pressure of the solution = mole fraction of solvent x vapor pressure of the pure solvent
2) Calculations
mass of ethylene glycol = density*volume = 1.115*51 = 56.865 g
moles of ethylene glycol --->56.865 g / 62.07 g/mol = 0.334 mol
Mass of water = 49*0.988 = 48.412 g
moles of water ---> 48.412 g / 18.0 g/mol = 2.69 mol
mole fraction of ethylene glycol = moles of ethylene glycol/total moles
mole fraction of ethylene glycol ---> 0.916 / (0.916+ 2.69) = 0.254
vapor pressure of solution = mole fraction * pure vapor pressure
vapor pressure of solution ---> 1torr * 0.254 = 0.254. torr
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