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An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d=1.114 g/mL;M=62.07 g/mol)...
An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d=1.114 g/mL; M=...
An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d=1.114 g/mL; M= 62.07 g/mol) and water (d=1.00 g/mL) at 20°C. The density of the mixture is 1.070 g/mL. Express the concentration of ethylene glycol as (a) volume percent I % v/v (b) mass percent % w/w (c) molarity м (d) molality (e) mole fraction
Be sure to answer all parts. An automobile antifreeze mixture is made by mixing equal volumes...
Be sure to answer all parts. An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d - 1.114 g/mL; M-62.07 g/mol) and water (d = 1.00 g/mL) at 20°C. The density of the mixture is! 1.070 g/mL. Express the concentration of ethylene glycol as (a) volume percent %v/v (b) mass percent % w/w (c) molarity d) malality (b) mass percent (e) molarity (d) molality (e) mole fraction
An solution of antifreeze is prepared by mixing 21.0mL of ethylene glycol (d = 1.11 g/mL; molar mass = 62.07 g/mol) with...
An solution of antifreeze is prepared by mixing 21.0mL of ethylene glycol (d = 1.11 g/mL; molar mass = 62.07 g/mol) with 50.0 mL H2O (d = 1.00 g/mL) at 25°C. If the density of the antifreeze solution is 1.07 g/mL, what is its molarity?
A solution of antifreeze is prepared by mixing 21.0mL of ethylene glycol (d = 1.11 g/mL;...
A solution of antifreeze is prepared by mixing 21.0mL of ethylene glycol (d = 1.11 g/mL; molar mass = 62.07 g/mol) with 50.0 mL H2O (d = 1.00 g/mL) at 25°C. If the density of the antifreeze solution is 1.07 g/mL, what is its molarity (M)?
A solution of antifreese is prepared by mixting 34.0mL of ethylene glycol (d=1.11g/mL; molar mass =62.07...
A solution of antifreese is prepared by mixting 34.0mL of ethylene glycol (d=1.11g/mL; molar mass =62.07 g/mol) with 50.0 mL H20 (d=1.00 g/mol) at 25 degrees celsius. if the density of the antifreeze solution is 1.07 g/ mL, what is the molarity?
An aqueous antifreeze solution is 31.0 % ethylene glycol (C2 H4 O2) by mass. The density...
An aqueous antifreeze solution is 31.0 % ethylene glycol (C2 H4 O2) by mass. The density of the solution is 1.05 g/cm3. Calculate the molality, molarity and mole fraction of the ethylene glycol Molality mol/kg Molarity mol/L Mole fraction
Ethylene glycol is used in automobile radiators as an antifreeze. Use the following information to determine the freezi...
Ethylene glycol is used in automobile radiators as an antifreeze. Use the following information to determine the freezing point of an antifreeze solution made by mixing 2.5 L of ethylene glycol with 2.5 L of water. Ethylene glycol is essentially nonvolatile and it does not dissociate in water. Molar mass of ethylene glycol = 62.1 g/mol; density of ethylene glycol = 1.11 g/mL; density of water = 1.00 g/mL; Kf for water = 1.86 degrees Celsius kg/mol
The antifreeze solution used in the majority of car radiators is a mixture of equal volumes...
The antifreeze solution used in the majority of car radiators is a mixture of equal volumes of ethylene glycol and water, with minor amounts of other additives that prevent corrosion. a) What is the mole fraction of ethylene glycol, C2H4(OH)2, in a solution prepared from 2.22 × 103 g of ethylene glycol and 2.00 × 103 g of water?
3. You prepare an antifreeze/coolant mixture by mixing 1.25 L of ethylene glycol (C2H602. density =...
3. You prepare an antifreeze/coolant mixture by mixing 1.25 L of ethylene glycol (C2H602. density = 1.12 g/mL) with 2.50 L of water (H2O. density = 1 g/mL). What are the freezing pom and boiling point of your antifreeze/coolant? (K=1.86 °C/m, K-0.51 °C/m)
Please explain. Thank you. (8) An antifreeze solution is prepared by mixing 719 mL of ethyl-...
Please explain. Thank you.
(8) An antifreeze solution is prepared by mixing 719 mL of ethyl- ene glycol (C2H4O2(1), M = 62.07 g/mol, d = 1.11 g/mL, struc- H-0-ċ-ċ-0-H ture shown at right) and 200 mL of water (H2O(1), M = HH 18.02 g/mol, d = 1.00 g/mL). The density of the resulting anti- freeze solution is equal to 1.10 g/mL. (a) [8 points] Calculate the volume of antifreeze solution prepared. (Hint: The volume of antifreeze solution is NOT equal...
An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d=1.114 g/mL; M= 62.07 g/mol) and water (d=1.00 g/mL) at 20°C. The density of the mixture is 1.070 g/mL. Express the concentration of ethylene glycol as (a) volume percent I % v/v (b) mass percent % w/w (c) molarity м (d) molality (e) mole fraction
Be sure to answer all parts. An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d - 1.114 g/mL; M-62.07 g/mol) and water (d = 1.00 g/mL) at 20°C. The density of the mixture is! 1.070 g/mL. Express the concentration of ethylene glycol as (a) volume percent %v/v (b) mass percent % w/w (c) molarity d) malality (b) mass percent (e) molarity (d) molality (e) mole fraction
An aqueous antifreeze solution is 31.0 % ethylene glycol (C2 H4 O2) by mass. The density of the solution is 1.05 g/cm3. Calculate the molality, molarity and mole fraction of the ethylene glycol Molality mol/kg Molarity mol/L Mole fraction
3. You prepare an antifreeze/coolant mixture by mixing 1.25 L of ethylene glycol (C2H602. density = 1.12 g/mL) with 2.50 L of water (H2O. density = 1 g/mL). What are the freezing pom and boiling point of your antifreeze/coolant? (K=1.86 °C/m, K-0.51 °C/m)
Please explain. Thank you.
(8) An antifreeze solution is prepared by mixing 719 mL of ethyl- ene glycol (C2H4O2(1), M = 62.07 g/mol, d = 1.11 g/mL, struc- H-0-ċ-ċ-0-H ture shown at right) and 200 mL of water (H2O(1), M = HH 18.02 g/mol, d = 1.00 g/mL). The density of the resulting anti- freeze solution is equal to 1.10 g/mL. (a) [8 points] Calculate the volume of antifreeze solution prepared. (Hint: The volume of antifreeze solution is NOT equal...
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