The LED stays on always.
The voltage at analog pin A0 = 0.66*5 V ( By voltage division).
In the output of analogRead 1024 is equivalent to 5 V.
So as 0.66*5 > 0.5*5 , first if statement is true and hence the led will be given high voltage and thus it will stay on.
An Arduino Uno is configured with the voltage divider connected to Analog input pin A0 as...
An Arduino Uno is configured with the voltage divider connected to Analog input pin AO as shown, and the code shown below is uploaded. What happens? testCodeA Arduino 1.8.11 Hourly Build 2019/10/29 11:12 Arduino Uno testCodeA #define LED 13 to sv 13o 5ke & void setup() { pinMode(LED, OUTPUT); to A 10KZ Ž ŞR void loop() { int voltage-analogRead(AO); if (voltage > 1024/2) digitalWrite(LED, HIGH); else digitalWrite(LED, LOW); GND GND Done compiling Sketch uses 778 bytes (2%) of program storage...
An Arduino Uno is configured with the voltage divider connected to Analog input pin AO as shown, and the code shown below is uploaded. What happens? testCodeA Arduino 1.8.11 Hourly Build 2019/10/29 11:12 Arduino testCodeA Uno #define LED 13 to SV 130 5ks § void setup() { pinMode(LED, OUTPUT); B toap ŹR 10 Kaş void loop 1 int voltage analogRead(AO); if (voltage > 1024/2) digitalWrite(LED, HIGH); else digitalWrite(LED, LOW); HOGNO Gong Done compiling Sketch uses 778 bytes (2%) of program...
I am doing an Arduino Uno project where I made a "Simon says" memory game with 3 neopixel LED strips and 3 - ultrasonics. I have them working independently but I need to combine the code so they work together. Here is what I have: Memory Game #define PLAYER_WAIT_TIME 2000 // The time allowed between button presses - 2s byte sequence[100]; // Storage for the light sequence byte curLen = 0; // Current length of the sequence byte inputCount =...