Question

An Arduino Uno is configured with the voltage divider connected to Analog input pin AO as shown, and the code shown below is uploaded. What happens? testCodeA Arduino 1.8.11 Hourly Build 2019/10/29 11:12 Arduino Uno testCodeA #define LED 13 to sv 13o 5ke & void setup() { pinMode(LED, OUTPUT); to A 10KZ Ž ŞR void loop() { int voltage-analogRead(AO); if (voltage > 1024/2) digitalWrite(LED, HIGH); else digitalWrite(LED, LOW); GND GND Done compiling Sketch uses 778 bytes (2%) of program storage space. Maximum is 32 Global variables use 9 bytes (0%) of dynamic memory, leaving 2039, Arduino/Genuino Uno on /dev/cu.usbmodem14101 O o Select one: a. The LED stays on b. The LED stays off c. The LED blinks on and off at a 1 Hz rate d. The LED blinks on and off at a 10 Hz e. The LED turns on when bright light shines on the circuit O O O

Answer 1

(b)The LED stays on always.

The voltage at analog pin A0 = 0.66*5 V ( By voltage division).

In the output of analogRead 1024 is equivalent to 5 V.

So as 0.66*5 > 0.5*5 , first if statement is true and hence the led will be given high voltage and thus it will stay on.