Part C If a room contains 25000 atoms of radon-222, how many atoms of radon-222 remain...

Question

Question

Answer 1

Answer #1

Initial number of atoms = 25000

Time = 15.2 days

Half-life = 3.8 days

So, n = 15.2/3.8 = 4

Hence, number of atoms remaining

= 25000 x (1/2)⁴

= 1600

If that doesn't work, try 1500

Comment if any problem

Answer 2

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