Question

In a sample of 40 adults, the mean assembly time for a child's swing set was...

In a sample of 40 adults, the mean assembly time for a child's swing set was 1.75 hours with a standard deviation of 0.80 hours. The makers of the swing set claim the average assembly time is less than 2 hours. Test their claim at the 0.10 significance level.

(a) What type of test is this?

This is a left-tailed test.

This is a right-tailed test.    

This is a two-tailed test.


(b) What is the test statistic? Round your answer to 2 decimal places.
t

x

=

(c) Use software to get the P-value of the test statistic. Round to 4 decimal places.
P-value =

(d) What is the conclusion regarding the null hypothesis?

reject H0

fail to reject H0    


(e) Choose the appropriate concluding statement.

The data supports the claim that the mean assembly time is less than 2 hours.

There is not enough data to support the claim that the mean assembly time is less than 2 hours.     

We reject the claim that the mean assembly time is less than 2 hours.

We have proven that that the mean assembly time is less than 2 hours.

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Answer #1

a)

H0: \mu >= 2

Ha: \mu < 2

This is left tailed test.

b)

Test statistics

t = (\bar{x} - \mu ) / ( S / sqrt(n) )

= (1.75 - 2) / (0.80 / sqrt(40) )

= -1.98

c)

From T table,

With test statistics 1.98 and df of 39,

p-value = 0.0274

d)

Since p-value < 0.10 level, Reject H0.

e)

The data supports the claim that the mean assembly time is less than 2 hours.

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