Question

would appreciate any help on this with explanation please. thank you

A chemist prepares a solution of sodium nitrate NaNO3 by..

A chemist prepares a solution of sodium nitrate NaNO3 by measuring out 192. umol of sodium nitrate into a 500. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mmol/L of the chemist's sodium nitrate solution. Be sure your answer has the correct number of significant digits. x 5 ?

Answer 1

1 mol = 100 mmol = 100 umol .: 103 mmol = 106 umo) 1 mmol = 10 umol 1 mmol 103 umo I 10 = 1 = 103 umol 1 mmol Concentration = mol Volume (Litre) volume = 500 mL = 0.500 litre Concentration = 192 umol 0.500 L = 384 umos x (1) 384 mmol 103 = 0.384 = 0.384 mmol/ = 3.84 x 10-2 mmoly s