Question

Draw the structure of the compound C3H4Cl2O from its proton NMR spectrum below. Please explain.

Draw the structure of the compound CH CI O from its proton (1) NMR spectrum below. Fust-order spin-spin splitting rules and equal coupling constants can be assumed. (Detailed analysis of any non-first order portions of the spectrum will not be required) Integral ratios to the nearest whole number are left to right) 1:3 Flash Installation and Troubleshooting Used with from At Checa Co Inc (purty at 2.30 pm) Chemical shift: 1.29 ppm 387 Hz CROSSHAIRS 5Y ZOOM MEASURE Chemical shift (ppm) (Use your cursor to read the chemical shift scale. Spin-spin splitting multiplets can be expanded using the "Zoom" and y-acis expansion"X5Y") tools.) • You do not have to consider stereochemistry • You do not have to explicitly draw Hatoms. . Do not include lone pairs in your answer. They will not be considered in the grading

Answer 1

The degree of unsaturation for the compound C3H4Cl2O can be calculated using following formula, DoU = (20)+2+N-X-H Here, c= number of carbons (3), N= number of nitrogens (O),X = number of halogens (2) and H= number of hydrogens (4) (2 x 3)+2+0-2-4_4 DOU = Therefore, degree of unsaturation in the given compound is 1. 1H NMR analysis- There are 2 set of proton in the NMR Signal at 4.65 (9) corresponds to attachment to CH3 Signal at 1.8 (d) correspond to CH The most probable structure of the compound is shown below, 4.65 (9) 1.8 (d)