Question

Draw the structure of the compound C3H3CI3 from its proton (H) NMR spectrum below. First-order spin-spin splitting rules and equal coupling constants can be assumed. (Detailed analysis of any non-first order portions of the spectrum will not be required.) Integral ratios to the nearest whole number are (left to right) 1:2 Flash Installation and Troubleshooting Solvent CDCl Used with permission from Aldrich Chemical Co., Inc (Impurities at 3.34, 4.05, & 4.07 ppm) Chemical shift x5 Y ZOOM MEASURE 15 0.0 30 4.5 6.0 7.5 9.0 Chemical shift, & (ppm) (Use your cursor to read the chemical shift scale. Spin-spin splitting multiplets can be expanded using the "Zoom" and y-axis expansion("x5 Y") tools.) You do not have to consider stereochemistry. You do not have to explicitly draw H atoms Do not include lone pairs in your answer. They will not be considered in the grading Previous Nex

Answer 1

Answer - 11 M. F- Callzcla Degree of Unsaturation = 1. "The one degree of unsaturabom indicate the presence of ac or ring. 2) IH NMR spectrum Integral sabo ok two NMR Peak Iscom lekt to right is 1:2 înclicate that Peak at 6.15 produced by fH and second Peaks at S 4.60 Produced by 2H 6.15 (t, 14) = "/c or Hug=c cil 4.40(d, 24) =(1-cu- c-H 06 el-cthc=0 The correct possible structure is 4.401d) CHo-cl CU 6.15(+)