Question

Draw the structure of the compound C₆H₅ClO from its proton (¹H) NMR spectrum below.

First-order spin-spin splitting rules and equal coupling constants can be assumed. (Detailed analysis of any non-first order portions of the spectrum will not be required.)

Integral ratios to the nearest whole number are (left to right) 2:2:1.

Flash Installation and Troubleshooting

graph data : 7.18 2153HZ 6.77. 2031Hz 5.25 1575HZ .01. 2 Hz

Draw the structure of the compound CH CIO from its proton ("H) NMR spectrum below. First-order spin-spin splitting rules and equal coupling constants can be assumed. (Detailed analysis of any non-first order portions of the spectrum will not be required.) Integral ratios to the nearest whole number are left to right) 2:2:1. Flash Installation and Troubleshooting Used with permission from Aldrich Chemical Co., Inc. Solvent CDCI Chemical shift: 7.26 ppm 2179 Hz X5 Y ZOOM MEASURE u sole do 15 7.5 Chemical shift, 8 (ppm) 9.0 (Use your cursor to read the chemical shift scale. Spin-spin splitting multiplets can be expanded using the “Zoom" and y-axis expansion("x5 Y") tools.) • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • Do not include lone pairs in your answer. They will not be considered in the grading.

Answer 1

CoH5C10 * 'H NMR : There are four (4) protons in the aromatic region which means bengene ring is present The one chloo grouq suggests that al is present as substituent Fri 10 on the bengene ring. The equal ralio of aromahe prolons suggests that the molecule symmenical proten, the prolon a broad peak) conresponds to the OH Stuchere: