A solution is formed by mixing 50.0 mL of 9.6 MNaX with 50,0 mL of 1.0...

Question

Question

A solution is formed by mixing 50.0 mL of 9.6 MNaX with 50,0 mL of 1.0 x 108 M CuNO3. Assume that Cut forms complex ions with

Answer 1

Answer #1

Millimole of Cu⁺ taken = 50.0ml × 1.0×10^-3mol/L = 0.050mmol

MilliMole of X^- taken = 50.0ml × 9.6mol/L = 480mmol

Since the value of equilibrium constant is very large , that means almost all of Cu⁺ is converted into complex form .

[CuX₃^2-] = 0.050mol/100.0mL = 5.0×10^-4 M

[X^-] = (480-3×5)mmol/100.0mL = 4.65 M

[Cu⁺] = [CuX₃^2-]/([X]³.K) = 5.0×10^-4/(1.0×10⁹ × 4.65³)

= 4.97×10^-15 M

= 5.0×10^-15 M.

[CuX₂^-] = K₁.K₂.[Cu⁺][X^-]² = 1.0×10⁶×4.97×10^-15×(4.65)²

= 2.3×10^-10 M

Answer :

(a) [CuX₃^2-] = 5.0×10^-4 M

(b) [CuX₂^-] = 2.3×10^-10 M

(c) [Cu⁺] = 5.0×10^-15 M

Answer 2

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