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A solution is formed by mixing 50.0 mL of 8.9 MNaX with 50.0 mL of 6.2 x 10-3M CUNO3. Assume that Cut forms complex ions with

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Concentration of NaX in 50 ml=[NaX]= {(50×8.9)/1000}Mole = 0.445 Mole

Concentration of CuNO​​​3​​ in the solution = [ CuNO​​​3​​ ] =

[{(6.2×10-3)×50}/1000}]moles = 3.1 ×10-4 moles

Ceutl-CeuNo3.1 X104 Cx-= [Nax Noro Ceux KCeutCx 0.445 ms)es Caux-K, CeutI Ex- Leux- C6x10 X3.1x 10x 0. a ys) meler Ceax- O. D

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