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A solution is made by equilibrating the two solids calcium sulfide (Ksp = 8.0×10-6) and calcium...

A solution is made by equilibrating the two solids calcium sulfide (Ksp = 8.0×10-6) and calcium chromate (Ksp = 7.1×10-4) with water. What are the concentrations of the three ions at equilibrium, if some of each of the solids remain?

[Ca2+] = M

[S2-] = M

[CrO42-] = M

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Answer #1

Ksp Cas(o Kspe Ca2+ + Cra CaCra caJ 8x 10 t5)(S) 2t Kspi Stt Sis2 8 x 10 CatTevo Ksps 2 7-1X10 SS+ S (3 (2 8 x IS 7.1x(0 S1+SPultig value SI im 3 X16- (12496)54 St 12685,-71X10 en solvig M Sa63 x1 O S 112.68 S2 S 71X io KaJ= Ca) Si+ s aag 163 x1o M

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