Question

Explain how 350. mL of 0.650 molar calcium acetate can be prepared from solid magensium acetate?

How would you prepare 1.75 liters of 0.750 molar sodium hydroxide if the course of sodium hydroxide was 3.5 liter bottle of 2.55 M sodium hydroxide?

Calculate the maximum mass of sodium phosphate that can be recovered from 225 mL of 0.85 M aqueous sodium phosphate?

Calculate the maximum volume of 1.25 M NaOH that can be neutralized by 4.00 liters of:

0.75 M HClO4

0.75 M H2SO4

A beaker contains a solution composed of 250 mL of water and 7.5 grams of an unknown soluble solute. How could you determine if the solits is a strong electrolyte, weak electrolyte, or non electrolyte?

Answer 1

350. mL of 0.650 molar calcium acetate solution is to be prepared from solid magnesium acetate.

Convert unit of volume from mL to L by dividing with 1000

$\frac{350. \ mL}{1000 \ mL/L}=0.350 \ L$

Obtain the number of moles of calcium acetate by multiplying volume (in L) with molarity.

Number of moles of calcium acetate $0.350 \ L \times 0.650 \ mol/L=0.2275 \ mol$

Molar mass of calcium acetate is 158.2 g/mol.

Calculate mass of solid calcium acetate required by multiplying molar mass with number of moles.

$158.2 \ g/mol \times 0.2275 \ mol=35.99 \ g \simeq 36.0 \ g$

Dissolve 36.0 g of calcium aetate in minimum amount of water and dilute the solution (with water) to a total volume of 350. mL.