ne:.. PSID# ...... ) Write a balanced half-reaction for the oxidizing agent in the following reaction...
Table 20.1 Half Reaction E°(V). F2 (g) + 2e →2F (aq) +2.87 Cl2 (g) + 2e → 2CV (aq) +1.359 Br2 (1) + 2e → 2Br (aq) +1.065 O2 (g) + 4H+ (aq) + 4e → 2H20 (1)+1.23 Agt te → Ag (s) +0.799 Fe3+ (aq) + € → Fe2+ (aq) +0.771 12 (s) + 2e → 21+ (aq) +0.536 Cu2+ + 2e → Cu(s) +0.34 2H+ + 2e → H2 (g) Pb2+ + 2e → Pb (s) -0.126 Ni2+...
A chemist designs a galvanic cell that uses these two half-reactions: standard reduction potential half-reaction + O2(9)+4 H (aq)+4e' 2H20) = 1.23 V red Ered Fe+. (аq) Fe3(aq)+e = +0.771 V Answer the following questions about thiss cell Write a balanced equation for the half-reaction that happens at the cathode Write a balanced equation for the half-reaction that happens at the anode Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous...
A certain half-reaction has a standard reduction potential E = -0.45 V. An engineer proposes using this half-reaction at the cathode of a galvanic cell that must provide at least 1.00 V of electrical power. The cell will operate under standard conditions Note for advanced students: assume the engineer requires this half-reaction to happen at the cathode of the cell. 0-0 . " Is there a minimum standard reduction potential that the half-reaction used at the anode of this cell...
A certain half-reaction has a standard reduction potential E Ted =-0.99 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must provide at least 0.90 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell O- Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have?...
Fill in the Blanks Ered (V) 0.68 0.52 0.40 0.34 0.16 0 Half Reaction Ered (V) Half Reaction F2+2e →2F 2.87 02 + 2H+ 2e →H,O, Ag?+ e → Ag 1.99 Cute → Cu Code → CO2 1.82 O2 + 2H,0 + 4e → 40H H,02 + 2H+ + 2e → 2H,0 1.78 Cu2+ + 2e → Cu Ce+ + → Ce+ 1.70 Cu2+ e → Cu PbO, + 4H* +502 +2e → PbSO4 + 2H,0 1.69 2H*+2e → H2...