Question

Titration ol Acids and Bases 20 A Standardization of Sadium Hydroxide (NO) solution Masal bodle Me 0.10394 tassium w auding Noled Molar al CF Average m arily Show your c Standard deviation ons for molarity and and devi B. Analysis of an unknown Acid Maafknowned Final bort ding 0.9012 13.20 MIDT

Please help me find the Molarity of NaOH of part A and the mass of KHP in the unknown and the Percent of KHP in the unknown

Answer 1

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qitu: standardization of Naon using kHP Naot! + KH($ 404 ag] =>KNaçetely + 4400) Solution: mass 9 kHP = 0.20399 moles of KHP = mass - 0.2039 molar mass g ketP= 204-28 gmot! nolar mass 204.2d 9 moet = 9.988154 moles. I mole of KHR reacts with Imole of Nach Quas domol of KHP reacts with 9.988109 9.98 X10 moles of KCHP required 9.98 810 4 moles of NaOH

volume of NaOH = 10.85m1 = 10.858103 L molarity of Naoth = moles - 9.988109 Millor mass 10 = 9.1988102 M volume in 10.858103 molarity of NaOH = 9• 198X102 m) (6 Analysis of unknown acide mass 9 unknown acid = 030739 Final burcite reding i burete reding (volume NaoH) 13.2001 = 13.20mi .. moles of NaOH = volume (L) x concentration - 12.200103 L x 9. 1988150 M = 1.21x10 3 molle in moles of NaOH = moles of kHP = 1.2a xios moles. mass of KHP in uniknown = moles amolar mass 1.21X108 x 204dd = 0.2489 A CHP mass of ICHP in canicnown = 0.248 g). i % KHP in unknown = 0.248×100 = 0.3072 80.71.1