using energy conservation
kE = 0.5 m v^2
1.02* 10^-17 = 0.5* 9.11* 10^-31 v^2
v = 4.732* 10^6 m/s
acceleration acts on particle
a = v^2/2d = (4.732* 10^6)^2 / ( 2* 0.13)
a = 8.613* 10^13 m/s^2
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a)
as per equilibrium of forces
qE = ma
E = 9.11* 10^-31* 8.613* 10^13 / ( 1.6*10^-19)
E = 490. 38 N/C
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b)
t = v/a = 5.494* 10^-8 = 54.94 ns
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c)
direction : opposite to initial direction
a = 8.613* 10^13 m/s^2
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