Question

Each of the electrons in a particle beam has a kinetic energy of 1.88 x 10-17). The mass of an electron is 9.11 x 10-31 kg. (a) What is the magnitude of the uniform electric field (pointing in the direction of the electrons' movement) that will stop these electrons in a distance of 14.0 cm? 40) 839 N/C (b) How long will it take to stop the electrons ? 4.9) 4.30e-8 x Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. ns (c) After the electrons stop, the electric field will continue to act on them, causing the electrons to accelerate in a direction opposite to the field with a magnitude of acceleration of ... 4.9 1.14e-14 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. m/s2

Answer 1

Eneogy of moving electone 1.88 x 10-29 Mess of electoon = 9.14 x 1034 kg CaTo Stop these electron K.E. Obs electron - P.t of elecron : k = e. Ex Here, OC - 14.0 cm = 14.0 x102 m. E= k -- 1.88 X4017 eice 7.6x1079 x 14x102 T TE=839 NIC (6) electron : Time Here require to we can Vodit Stop use Na Initial speed as Acceleration of ta Time require of electron electron to 870p To tind acceleration : Fae. E = mia (1.6*40295 8392 $39) 9.21 x 2031 - = 1.47 klo 14 mlez Part. 1.47 X 10^4 m/s2 Ansert 2 = 1.88 ryo .-17 | 1 me (t) = 4.37 x 10 te 6.42 X 106 - 1.47 x 2074 12 (1.88 x 20 277 Y 9.12 x4031 IN=6.42x 406 mis to 0.437 ns scanned with CamScanner