Let x be the value drawn from a normal distribution with mean and standard deviation
The z score of x is .
The value of x in terms of z score, mean and standard deviation is
This indicates that the value of x is mean plus z standard deviations. Other way of stating this is, x is z standard deviations away from the mean.
When the z score of a value is larger that 2, it means that the value is more than 2 standard deviations away from the average (or mean).
It terms of probability we can get the P(Z>2) = 1-P(Z<2) = 1-(0.5+0.4772)=0.0228 (using standard normal tables)
This means that the probability of observing a value (with z score more than 2) is only 0.0228. That is there is only a 2.3% chance of observing this value and and hence it is not a common value.
What does it mean when the Z score of a value is less than -2?
What does it mean when the Z score of a value is between -2 and 2?
Suppose that student’s z score is 3.00 what does this mean? discuss in terms of units of standard deviation It means the value defined by z-score is 3 standard deviations away from the mean value. Discuss in terms of its percentile score. In terms of percentile score, its mean amount of data lies below the value. Z=3 represent the 99.87 the percentile. 4. How does this student’s z score differ from another student whose z score is -3.00 5. If...
The larger the absolute value of the z score (regardless of its sign), then A. the higher its equivalent raw score. B. the further it is from the mean. C. the closer its equivalent raw score must be to the mean.
Consider a value to be significantly low if it's z score less than or equal to -2 or consider a value to be significantally high if it's z score is greater than or equal to 2. A test is used to assess readiness for college. In recent year, the mean test score was 22.8 and the standard deviation was 5.3. Identify the test scores that are significantly low or significantly high. What test scores are significantly low? What test scores are significantly high? (Please...
Consider a value to be significantly low if its z score less than or equal to - 2 or consider a value to be significantly high if its z score is greater than or equal to 2. A data set lists weights (grams) of a type of coin. Those weights have a mean of 5.36344 g and a standard deviation of 0.05415g. Identity the weights that are significantly low or significantly high. What weights are significantly low Select the correct answer below...
Consider a value to be significantly Id if its z score less than or equal to - 2 or consider a value to be significantly high if its z score is greater than or equal to 2. A test is used to assess readiness for college. In a recent year, the mean test score was 19.1 and the standard deviation was 5.1. Identify the test scores that are significantly low or significantly high.
Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly high if its z score is greater than or equal to 2. A test is used to assess readiness for college. In a recent year, the mean test score was 19.519.5 and the standard deviation was 4.74.7. Identify the test scores that are significantly low or significantly high.
Consider a value to be significantly low if its z score less than or equal to minus2 or consider a value to be significantly high if its z score is greater than or equal to 2. A test is used to assess readiness for college. In a recent year, the mean test score was 20.2 and the standard deviation was 5.2. Identify the test scores that are significantly low or significantly high. What test scores are significantly low? Select the...
Consider a value to be significantly low if its z score less than or equal to - 2 or consider a value to be significantly high if its z score is greater than or equal to 2. A test is used to assess readiness for college. In a recent year, the mean test score was 22.3 and the standard deviation was 4.5. Identify the test scores that are significantly low or significantly high What test scores are significantly low? Select...