Mass percent of water present in the hydrated LiClO4 can be calculated as follows, given that mass of hydrated sample ( sample which contains water) and mass of anhydrated sample ( sample in which no water content is present), so that we can find the total mass of water which was present in the hydrated sample.
Mass of hydrated sample = 7.50 g
Mass of anhydrated sample = 4.97 g
Mass of water = Mass of hydrated sample - Mass of anhydrated
= 7.50 - 4.97
= 2.53 g
Mass percent of water=Mass of water/Mass of hydrated sample × 100
= 2.53/7.50 × 100
= 33.73 %
So, mass percent of water present in the hydrated LiClO4 sample is 33.73%
4. When a 7.50 g sample of hydrated LiClo, is heated to drive off all the...
When a 7.50 g sample of hydrated LiClO, is heated to drive off all the water, the anhydrous residue that remains has a mass of 4.97 g. What is the mass percent of water in the hydrate?
A hydrated form of copper sulfate (CuSO4⋅?H2O) is heated to drive off all of the water. If there is initially 7.28 g of hydrated salt and there is 4.07 g of anhydrous CuSO4 after heating, find the number of water molecules associated with each CuSO4 formula unit. x = ?
A hydrated form of copper sulfate (CuSO4 xH,O) is heated to drive off all of the water. If there is initially 9.22 g of hydrated salt and there is 5.89 g of anhydrous CuSo, after heating, find the number of water molecules associated with each CUSO4 formula unit.
5. A 1.547 g sample of CuSO, XH,O is heated to drive off the water leaving behind 0.989 g of anhydrous Cuso, What is the value of x for this hydrate?
A student heated a sample of a hydrated salt and obtained the following data: Grams of hydrated salt used: 1.0000 gram Grams of anhydrous salt (147 g/mole) recovered: 0.8033 grams Grams of water vapour (18 g/mole) lost: 0.1967 grams Determine the percentage by mass of water in this hydrate. (1) How many water molecules, "X", are bonded to this hydrated salt, salt. X H20? (2)
A 1.803-g sample of gypsum, a hydrated salt of calciumsulfate, CaSO4, is heated in a crucible until a constantmass is reached. The mass of the anhydrous CaSO4 salt is1.426-g. Calculate the percent by mass of water in the hydratedcalcium sulfate salt. Also, calculate the moles of water removedand the moles of anhydrous CaSO4 remaining in thecrucible. And, finally, What is the formula of the hydrated calciumsulfate; that is, what is the whole-number mole ratio of calciumsulfate to water? Please show...
CUSU 420 4. A 1.082 g sample of Niso, . x H2O is heated to drive off the water leaving behind 0.596 g of anhydrous NiSO4. a. How much water was removed? (15) 0.4869 b. How many moles of Niso, were in the sample? (15) 0.596 -0.00385 mol Nisou c. How many moles of water were in the hydrate? (15) 0.486-18=0.027 mol H2O d. What is mole ratio? (15) 0.0027 7.00 mol 0.00385
An experiment was performed to determine the percentage water content in a hydrated compound. A 15.67 g sample of a hydrate, magnesium carbonate was heated, without decomposing the carbonate, to drive off the water. The mass was reduced to 7.58 g. What is the percent water content?
Question five A 15.67 g sample of a hydrate of magnesium carbonate ( MOONH:O) was heated without decomposite the carbonate, to drive off the water. The mass was reduced to 7.58 g (Molar mass of MgCO: - 84313 Smol) (5 mark) A. What is the formula of the hydrate? B. Determine the percentate in the hydrated sit
15.67 g sample of a hydrate of magnesium carbonate was heated, without decomposing the carbonate, to drive off the water. The mass was reduced to 7.58 g. What is the formula of the hydrate? Name the hydrate