Question

can someone please help with this?

5. Below are two types of enzyme kinetics curves - make careful note of how the axes are different. For each condition below, give the letter(s) indicating the appropriate region(s) of the graph(s). a. Region(s) where the enzyme is saturated with substrate v, (mM/s) b. Region(s) showing equilibration 5 15 20 10 [S] (M) c. Region(s) where an initial velocity is able to be determined d. Region(s) where AG is zero [Product] (MM) 5 10 15 Time from start of reaction (sec) 20 e. Region(s) used to determine KM graphically

Answer 1

a. Since enzyme remains in low amount compared to the substrate, so, initially when the reaction did not start the enzyme was saturated by substrate. So, region D is that. In the first graph, Michaelis - Menten curve, maximum initial velocity is reached when substrate concentration is too high compared to enzyme concentration. So, region C is also the answer.

b. At equilibrium, rate of the forward and backward reaction becomes equal. So, eventually product concentration should not alter. So, region F is the answer.

c. The first graph is the plot of initial velocity vs substrate. So, everywhere we can measure that, A, B and C. For second graph, we can measure initial velocity from the slope of a tangent at t=0. So, at D region.

d. $\Delta G$ is zero only at the point of equilibrium. So, the answer is F.

e. We know from Michaelis-Menten equation K_M is the substrate concentration when velocity reaches half of the maximum value, i.e, here [S] at V₀ = 0.5 (V_max = 1) gives the K_M value. So, answer is B.