Question

part b: do the results from this sample validate the websites findings?

OH According to a travel website, workers in a certain country lead the world in vacation days, averaging 20 27 days per year. The following data show the number of paid vacation days for a random sample of 20 workers from this country. Complete parts a through below Nam 25 Due: Currea Construct a 99% confidence interval to estimate the average number of paid vacation days for workers from this country Atten The 10% confidence interval to estimate the average number of paid vacation days for workers from this country is from day to days. Late (Round to two decimal places as needed)

part c: what assumptions need to be made about this population?

Answer 1

a)

sample std dev ,    s = √(Σ(X- x̅ )²/(n-1) ) =   12.4900
Sample Size ,   n =    20
Sample Mean,    x̅ = ΣX/n =    24.0000

Level of Significance ,    α =    0.01          
degree of freedom=   DF=n-1=   19          
't value='   tα/2=   2.8609   [Excel formula =t.inv(α/2,df) ]      
                  
Standard Error , SE = s/√n =   12.4900   / √   20   =   2.7928
margin of error , E=t*SE =   2.8609   *   2.7928   =   7.9902
                  
confidence interval is                   
Interval Lower Limit = x̅ - E =    24.00   -   7.990156   =   16.0098
Interval Upper Limit = x̅ + E =    24.00   -   7.990156   =   31.9902
99%   confidence interval is (   16.01 < µ <   31.99 )

b)

Yes, because null hypothesis 20.27 is contained in confidence interval

c) population is assumed to be distributed as approx normally distributed