Question

Formula of salt NAO AC Mass of salt used 8.3145 Moles of salt 10 moles Change in Temperature (Tr-T) -1.6 Total mass of solution 150ml x.99 7g| ML) + 8.314. UUUUU 157.869 5.5% Weight percent of salt in solution (8.314/150 x 100 =5.5% Specific heat of solution 4.18J Ig t Heat change for solution (9soln) Heat change for the calorimeter (cal) Total heat change (total) Molar heat of solution of your salt

Answer 1

mole of salt = 8.314 g / 82.0343 g/mole = 0.101 mole.

Heat change of solution = m * s * dT = 157.86 g * 4.18 J / g-oC * (-1.6) oC = - 1055.8 J

heat change of calorimeter = heat capacity of calorimeter * dT = heat capacity of calorimeter * (-1.6) = [- 1.6 * heat capacity of calorimeter] = - 1.6 * x J

to get this need the heat capacity of calorimeter.

total heat change =  - [1055.8 + 1.6 * x ] J

molar heat of solution of your salt = {[1055.8 + 1.6 * x ] / 0.101 } J