Question

THERMOCHEMISTRY (Work for all calculations should be shown in questions 1 & 2 below) Calorimeter constant NAD AC Formula of salt 8.314.F Mass of salt used 0.101 m010 Moles of salt 8.314 9162.03)3 1male-10 Change in Temperature (T- T,) 219 C temp Firial temp. 203 'C 151.B%g Total mass of solution Id x.997g18.314 5.5% Weight percent of salt in solution S0X 100-S.5. Specific heat of solution Heat change for solution (gsoln) 151.8b x4.18 x1.6) 10SS,8 1G00 Heat change for the calórimeter (qcal) 1055.9 x Total heat change (hota) Molar heat of solution of your salt

Answer 1

Calorimeter constant = 278.6J/% Formeela of salt $ Naone op CH3COONA Mass of salt used = 8.3149 Moles of salt Mass of salt used L. 8.314 g Molar mass of salt (CH3COONa), 320343 glas? change in temperature ( Tp-T:) = 20.3-21.9) = -1.6*e = 0.101 mroles Total mass of solution= [150 (ml)x0.997(g/ml) + .314] - 157.8649 Weight percent of salt owing in the solution - 3:314 x100 - 5.54% specific heat of solution = 4:185/goe. Heat change for solution = (Psom) = 157.864*48(-16) 1 = a1055.793 Heat change for calorimeter (Pcal) = 27806XC-116) J .= -445.76J Total heat change (a total) = qsok & q cal = -1055.79+ 445.70 J = -1501055 J Molar heat of solution of the salt = 9 total i 8 Imol. of salt) 15-1800;55) 5/mot = + 14 866.83 99 = + 127.866 kJ/mot.