molarity of CH4 = no of moles/volume in L
= 0.305/1 = 0.305M
molarity of CCl4 = no of moles/volume in L
= 0.305/1 = 0.305M
------- CH4(g) + CCl4(g) ----------> 2CH2Cl2(g)
I ---- 0.305 ---- 0.305 -------------- 0
C---- -x ---- -x ------------------ 2x
E --- 0.305-x --- 0.305-x ------- 2x
kc = [CH2Cl2]^2/[CH4][CCl4]
9.52*10^-2 = (2x)^2/(0.305-x)(0.305-x)
9.52*10^-2 = (2x/(0.305-x)^2
0.3085 = 2x/(0.305-x)
0.3085*(0.305-x) = 2x
x = 0.04075
[CH4] = 0.305-x = 0.305-0.04075 = 0.26425M
[CCl4] = 0.305-x = 0.305-0.04075 = 0.26425M
[CH2Cl2] = 2x = 2*0.04075 = 0.0815M
molarity CO = no of moles/volume in L
= 1.87/1 = 1.87M
----- COCl2 ------------> CO(g) + Cl2(g)
I ----- 1.87 -------------- 0 ------- 0
C ---- - 0.0399 ------ 0.0399 --- 0.0399
E ---- 1.8301 ------ 0.0399 --- 0.0399
Kc = [CO][Cl2]/[COCl2]
= 0.0399*0.0399/1.8301
= 8.7*10^-4 >>>>answer
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