The equilibrium constant, Kc, for the following
reaction is 10.5 at 350 K.
2CH2Cl2(g)
>>CH4(g) +
CCl4(g)
Calculate the equilibrium concentrations of reactant and products
when 0.327 moles of
CH2Cl2 are introduced into a
1.00 L vessel at 350 K.
[CH2Cl2] | = | M |
[CH4] | = | M |
[CCl4] | = | M |
The equilibrium constant, Kc, for the following
reaction is 1.29×10-2 at
600 K.
COCl2(g) >>CO(g)
+ Cl2(g)
Calculate the equilibrium concentrations of reactant and products
when 0.275 moles of
COCl2(g) are introduced into a 1.00 L
vessel at 600 K.
[COCl2] | = | M |
[CO] | = | M |
[Cl2] | = | M |
The equilibrium constant, Kc, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) >>CH4(g) +...
The equilibrium constant, Kc, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) = CH4(g) + CCl4(g) Calculate the equilibrium concentrations of reactant and products when 0.294 moles of CH2Cl2 are introduced into a 1.00 L vessel at 350 K. [CH2Cl2] = ? M [CH4] = ? M [CCl4] = ? M
34) The equilibrium constant, Kc, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) <---> CH4(g) + CCl4(g) Calculate the equilibrium concentrations of reactant and products when 0.222 moles of CH2Cl2 are introduced into a 1.00 L vessel at 350K. [CH2Cl2] = ___ M [CH4] = ___ M [CCl4] = ___ M
a) The equilibrium constant, Kc, for the following reaction is 9.52×10-2at 350 K. CH4(g) + CCl4(g) -> 2 CH2Cl2(g) Calculate the equilibrium concentrations of reactants and product when 0.251 moles ofCH4and 0.251 moles of CCl4are introduced into a 1.00 L vessel at 350 K. [ CH4] = M [ CCl4] = M [ CH2Cl2] = M b) The equilibrium constant, Kc, for the following reaction is 1.20×10-2 at 500 K. PCl5(g) ->PCl3(g) + Cl2(g) Calculate the equilibrium concentrations of reactant...
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) = CH4(g) + CC14(9) Calculate the equilibrium concentrations of reactant and products when 0.377 moles of CH,Cl2 are introduced into a 1.00 L vessel at 350 K (CH2Cl2] = [CH4] = [CCl4] =
The equilibrium constant, Kc, for the following reaction is 9.52x10-2 at 350 K: CH4(8) + CC14(8) — 2CH2Cl2(g) Calculate the equilibrium concentrations of reactants and product when 0.305 moles of CH4 and 0.305 moles of CCl4 are introduced into a 1.00 L vessel at 350 K. [CH] = [CC14] = [CH2Cl2] = A student ran the following reaction in the laboratory at 531 K: COC12(8) CO(g) + Cl2(8) When she introduced 1.87 moles of COCl2(g) into a 1.00 liter container,...
The equilibrium constant, Kc, for the following reaction is 9.52×10-2 at 350 K: CH4(g) + CCl4(g) <---> 2CH2Cl2(g) Calculate the equilibrium concentrations of reactants and product when 0.343 moles of CH4 and 0.343 moles of CCl4 are introduced into a 1.00 L vessel at 350 K. [CH4] = M [CCl4] = M [CH2Cl2] = M
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(8) CH4(8) + CC14(8) Calculate the equilibrium concentrations of reactant and products when 0.242 moles of CH2Cl2 are introduced into a 1.00 L vessel at 350 K. M (CH2Cl2] [CH] [CC14] M M
The equilibrium constant, Kc, for the following reaction is 1.29×10-2 at 600 K. COCl2(g) ----> CO(g) + Cl2(g) Calculate the equilibrium concentrations of reactant and products when 0.362 moles of COCl2(g) are introduced into a 1.00 L vessel at 600 K. [COCl2] = _____ M [CO] = _____ M [Cl2] = ____ M
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) CH4(g) + CCl4(g) An equilibrium mixture of the three gases in a 1.00 L flask at 350 K contains 5.09E-2 M CH2Cl2, 0.165 M CH4 and 0.165 M CCl4. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.82E-2 mol of CH2Cl2(g) is added to the flask? [CH2Cl2] = M [CH4] = M [CCl4] = M
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) CH4(g) + CCl4(g) An equilibrium mixture of the three gases in a 1.00 L flask at 350 K contains 5.21×10-2 M CH2Cl2, 0.169 M CH4 and 0.169 M CCl4. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.139 mol of CCl4(g) is added to the flask? [CH2Cl2] = M [CH4] = M [CCl4] = M