Question

Given the kinetics data for each enzyme in the presence and absence of its inhibitor, determine the type of inhibition. 

Enzyme	K_(M)(mM)	V_(max)(mmol//s)
carbonic anhydrase	8,000	600,000
+ inhibitor A	12,000	600,000
chymotrypsin	5,000	100
+ inhibitor B	5,000	75
penicillinase	50	2,000
+ inhibitor C	30	1,500
lysozyme	6	0.5
+ inhibitor D	15	0.5
carboxypeptisase A	3	1,000
+ inhibitor E	3	800

Answer 1

The correct answer is:

Competitive = +inhibitor A & +inhibitor D

Non-Competitive = +inhibitor B & +inhibitor E

Uncompetitive = +inhibitor C

Answer 2

Page No for Enzyme Carbonic anhydrase (CA) - Enzyme Km (mm) Vmax (mmolle) CA 8,000 Goo,ooo CA+ Inh. A 12,000 600,000 In absence of inhibitor Ets k Es K, É +P Ez se Enzyme substrate Line weaver - Buok equation ES = Enzyme-substrale complex In presence of Ets k Inhibitor es key E +P E = En E I Et ESI - EstI Ę = [E][I] CE1] k' = [ES] [17 [ESI] x' = 1+ [I] x = 1 + [I] KI Teacher's Signature:

Line wearer Buck equation matc This is of linear equation type y = mx Intercept = x - X max = x - mon Intercept i A Vonax In absence of liebt inhibitor I VmX Intercept Intercept - - Umax = Interest - ® from the given data, Vmax does not change on adding inhibitor. It means [X'=1 from er. ④ and B In absence of inhibitor In presence of inhibitor slove = KM slope = x km Vmax Vmax KM 2 slope x Vmax km = slope X max ky

Page 3 In presence of Inhibitor KM value has been changed houm 8000 mM to 12 ovo mM. Vmax is same in both the cases. Ky she can be changed only if (slope / ) factor is changed It indicates x 71 x 1 As a cannot be negative from expression x= 1 + [I] . KI In this case x>l, x'=1 . It means inhibitor inhibits by binding with enzyme only. There is no ESI complex formation. This is Competitive inhibition

Page 4 for Enzyme Chymotopsin T Ka (mm) Enzyme E Umox (mmol/s) Enzyme 5ooo E + Inh B soo Linewearer Burk equation I = 1 + KM I In absence of inhibitor v Umor Umar hibitor 52 X + 2 km v Vmax Vmor is In presence of inhibitor In absence of inhibitor = L Vmox may = mar Intercept Intercept As it & Vmax is changed from 100 mmolls to 75 mmolls means x '&l. : 2>I. cannot be negative from the equation d'a [1] x KM Slope = km Vmax V mox

Pago Nos In presence of inhibitor In absence of Juhibelor KM ² slope X V more I KM 2 slope x V mox As KM value is same in both the cases . It means x= 1 In this case x= 1 an, a'>L, It means inhibitor inhibits by binding with enzyme-substrate compless. There is no Ef formation This is Uncompetititure inhibition For Enzyme Pencillinase Enzyme | Kalm M) Vmax (mmolla) E Et inhic 50 30 152 from the given data, it is clear that adding inhabitor both KM & Umex change. means 1 & 1 and a ll on It In this case xt1, 2 > It means inhibitor does inhibition by binding with enzyme as well as with enzyme substrate complex. This is Non-competitive of Mixed Inhibition

For Enzyme Lysozyme Page 6 Enzyme | K (mm) 1 moxe (mmolla) 0.5 E e Tu D It means x=1 V mox is same in both the cases. KM has been changed... x > 1. This is Competitive inhibition for Enzyme carboxypeptisase A I Enzyme I KalmM) I Vmax (mmolla) novo w E tinht I w sw Ky is same in both the cases Umox has changed i x> l T: This is Uncompetitive i x=1 e inhibition

Competitive Inhibition Non-Competitive inhibition Uncompetitive inhibition |=اه راه x>',2'> x=1,4'> Carbonicankydoose tinhibitor A Pencillinase + inhibitore Chymotopsin tinhibitor B Lyso enzyme + inhibitor D CarboxypeptisaseA tinhibitor E