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If the molar mass of toluene 92.6 g/mol, how much of toluene is needed to depress...

If the molar mass of toluene 92.6 g/mol, how much of toluene is needed to depress the freezing point of 200 g of benzene by 0.47 degrees Celsius? Kf= 5.12 C/m

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using, AT = Kg xm - 0.47 = 5.12xm m = 0.47 5.12 → mass of tot une 92.6 ton 200x10 3 = 0.47 5:12 mass of todune - 0.47x200x10n

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