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The population mean and standard deviation are given below. Find the required probability and determine whether...

The population mean and standard deviation are given below. Find the required probability and determine whether the given sample mean would be considered unusual. For a sample of n equals 66​, find the probability of a sample mean being less than 20.6 if mu equals 21 and sigma equals 1.16. LOADING... Click the icon to view page 1 of the standard normal table. LOADING... Click the icon to view page 2 of the standard normal table. For a sample of n equals 66​, the probability of a sample mean being less than 20.6 if mu equals 21 and sigma equals1.16 is

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Answer #1

Here, μ = 21, σ = 0.1429and x = 20.6. We need to compute P(X <= 20.6). The corresponding z-value is calculated using Central Limit Theorem

z = (x - μ)/σ
z = (20.6 - 21)/0.1429 = -2.8

Therefore,
P(X <= 20.6) = P(z <= (20.6 - 21)/0.1429)
= P(z <= -2.8)
= 0.0026


yes, the given sample mean would be considered unusual

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