The population mean and standard deviation are given below. Find the required probability and determine whether the given sample mean would be considered unusual.
For a sample of
nequals=60
find the probability of a sample mean being less than
24.1
if
muμequals=24
sigma=1.33
Sol:
xbar follows normal distibution with mean=xbar=24
s=sigma/sqrt(n)=1.33/sqrt(60)=0.1717023
P(Xbar<24.1)
z=xbar-mu/s
=24.1-24/0.1717023
=0.1/0.1717023
z= 0.5824034
P(Z< 0.5824034)
=0.7199
ANSWER:
the probability of a sample mean being less than 24.1=0.7199
it is not unusual
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