Part AH X = 90 kJ , ASrxn = – 149 J/K , T = 293...

Question

Question

Answer 1

Answer #1

We have the relation, dG = dH – TdS

Part C:

Here, dHrxn = 90 kJ , dSrxn = -149 J/K = -0.149 kJ/K, T = 293 K

dG = 90 + (293 x 0.149) = 133.66 kJ

Part D:

Here, dHrxn = -90 kJ , dSrxn = 149 J/K = 0.149 kJ/K, T = 401 K

dG = -90 - (401 x 0.149) = -149.75 kJ

Answer 2

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