Question

Review Constants 1 Periodic Table AHX = - 127 kJ ; ASix = – 260 J/K;T = 302 K Calculate the change in Gibbs free energy for each of the following sets of AHX, ASixn, and T. (Assume that all reactants and products are in their standard states.) Express your answer as an integer. CO ALQ R O a ? AGixn = Submit Request Answer Part D AHIX = 127 kJ ; ASix = – 260 J/K;T = 600 K Express your answer as an integer. % ALQ R o 2 ? AGfxn=

Answer 1

The formula for calculating delta G is as follows:

AG = AH-TAS

Delta H = -127 KJ

Delta S = - 0.260 KJ/K

For part C:

$\Delta G$ = -127 - (302*(-0.260))

$\Delta G$ = - 48.48 KJ

Therefore, - 49 is the answer.

For part D:

$\Delta G$ = -127 - (600*(-0.260))

$\Delta G$ = 29 KJ

Therefore, 29 is the answer.

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