Question

Part A AHX = 133 kJ, ASP = - 247J/K,T=307 K. Express your answer using three significant figures. View Available Hint(s) V AED O ? ASuniv J/K Submit Part B AH -133 kJ. A S x=247 J/K T = 307 K. Express your answer using three significant figures. View Available Hint(s) VO AED - O ? ASumiy A.Sun'v J/K Submit

Answer 1

solution 4Hyyon means or, denote enthalpy of reaction. Here reaction is sy tem, so, enthalpy of reaction is actually enthalpy of system. it system release heat surrounding will absorb this heat. it system will release absorb heat then this (sacane amount surroundin heat now, as universe - A Seystem + 4s surrounding, here, Seys = 7 Syxn. All surrounding :AS = AS Surrounding . T Lor, as here, at surround = - 44 system. it system release heat surrounding will absorb same amount of heat. As witounding 4 tsystem i Asswot 7 Å system = 45 surtounding = -

I part-A A Hoon = 133KJ. =) Al system = 133 KJ as reaction is system L 4 t sys is positive, that means system absorbed heat so surrounding will release same amount of heat. At suor = - 4H system = - 133 KI. 4 sswer = 4ts will minus sign indicate heat it released by me SW'Ulounding L -133 KB 307K -33% 103 307 K -) A Swin ___ 4 Sürr = – 433'22 J/K. given, asixn = -247J/K ) AS sys ==247/ & AS univ = 4 Says + 4S sure =-347 3/K – 433:22 J/K. A Suniv. =-680. J/K Tin 3 signitieront tigare Note & please input the above value with decimal point i.e. -680..

part-B | AHDxn = - 133 K J. AHSY = -133 KU. - - #swer 4 # $44. 4 Suvel = Attsys => AS surr (-133 kJ) - A53 BI 307 K 1334 103 I 307 k = 433'22 J/K 4 Syyn = 7 45sys E247 IK 15.simig I reaction i AS unir = Assyst Assure = 247 3/K + 433.22 J/K. 4 Sunir = 680. Tin 3 o significant figure

parte hun = -133 A 4 Hsys = -133 kJ - A Hsure =- . Assure = 4 . 4 H sys =) 45 suve - - 4 Hsys - T 3- [133 KB) 307K = 133 X10° 307K = 433:22 J/. · L Syston Asix = -247 J/K. .: 45sys = -247 J/K r as sesetion is 7 : AS univ = Asyys + As surrounding = -247 J/K + 433' 22 I 4 Sunix = 186 J/K I in a significant EFami 1

When, T = 549K 4 Hixn = - 133kJ 4Hsys - 133 KJ A Asus 4 Hourr 4 Ssure = = 45 sur =- 4 Hsys =-(-133 kJ) 549K 133X10²3 549K = a42' Asixxn = -247 J/K. 3) 459y3 = -247 3/. 4 Suniv = 4 Says + 4 sure = -247 + 242:26 I/K F/K J/K I in two significant 4 Suniv = -4.7 tiguie]