Question

Part D only plz.

Learning Goal:

To practice Problem-Solving Strategy for general problems.

Two hockey pucks, labeled A and B, are initially at rest on a smooth ice surface and are separated by a distance of 18.0 m . Simultaneously, each puck is given a quick push, and they begin to slide directly toward each other. Puck A moves with a speed of 1.50 m/s , and puck B moves with a speed of 2.70 m/s .

What is the distance covered by puck A by the time the two pucks collide?

Unknown 4, (h),-(#1),-21 Review 2p A Since we selected a coordinate system whose origin is Note that your target variable is the distance covered by pudA by the ธ me the two pucks collide that is, the initial position of puckA,0 m and your target variable becomes simply z a 1 A Learning Goal: To practico Problom-Solving Stratagy for gonoral problems. In addition to the pictorial representaion, you could also draw a graphical representation of the problam, such as plotting (on the same graph) the position of each puck as a functi time. Two hockey pucks, labeled A and B, are initaly at rest on a smcoth ice surfaco and are soparatod by a distanco of 18.0 m. Simultaneously, each puck is givon a quick push, and thoy bogin to slide diroctly toward oach other. Puck A movas with a spood of 1.50 m/s, and puck B moves with a spaod of 2.70 m/s Solve Now you can uso the information and the insights hat you havo acoumulated to construct the nocoseary mathomatical raprosontation of this problom and to derivo the solution. Hare are two relevant equations that you may not yet know how to derive (the notation corresponds to the notation used in the pictorial representation above): What is the distance covarod by puck A by tho time the two pucks colldo? and (Since()B has a negatve value anhas a positive value, the pucks are moving in opposite directions.) Part D VWhat is 1, he distance that puck A covers prior to the collision? Express your answer in meters to three significant figures. Do not include units in your answer View Available Hint(s) #1-18.5 You havo already submittod this answor. Entor a new answer No arodit lost. Try again. Submit

Answer 1

d = distance between puck A and puck B = 18 m

v_A = speed of puck A towards puck B = 1.50 m/s

v_B = speed of puck B towards puck A = 2.70 m/s

t = time taken to meet

time taken to meet is given as

t = d/(v_A + v_B)

inserting the values

t = 18/(1.50 + 2.70)

t = 4.3 sec

distance traveled by puck A is given as

X_A = v_A t

X_A = 1.50 x 4.3

X_A = 6.5 m