Given
Volume = 15 L
Mass of nitrogen= 84.9 g
Temperature= 25°C = (25+273) K = 298 K
Using ideal gas equation
PV = nRT
==>
P = nRT/V
R is universal gas constant = 0.08206 L atm/mol K
n is the no of moles
No of moles= mass/ molar mass
Molar mass of nitrogen gas(N2) = 28 g/mol
So
No of moles= 84.9 g/28 g/mol
= 3.03 moles
Now
P = (3.03 moles)*(0.08206 L atm/mol K)(298 K)/15 L
= 4.94 atm
• A steel cylinder with a volume of 15.0 L is filled with 84.9 g of...
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