Zn(s) + HCl(l) ==> ZnCl2(aq) + H2(g)
Balancing equation
Consider Zn
It is already balanced
Consider H
In the product side there are 2 H so multiply HCl by 2 on reactant side
Zn(s) + 2HCl(l) ==> ZnCl2(aq) + H2(g)
Now Cl is also balanced
So the balanced reaction is
Zn(s) + 2 HCl(l) ==> ZnCl2(aq) + H2(g)
8) Balance the equation for the following reaction. Zn(s) + HCl(1) → ZnCl2(aq) + H2(g) -
Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g)Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 2.00 M HCl(aq)2.00 M HCl(aq) are required to react with 8.55 g Zn(s)?
In the following equation, what is oxidized? Zn(s) + 2HCl(aq) ---> ZnCl2(aq) + H2(g) Group of answer choices Zinc Hydrogen in HCl Chlorine in HCl This is not an oxidation-reduction reaction
Determine AS for the reaction to form 45.92 g of, Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g), given (answer in J) Substance Sº (J/mol · K) Zn(s) 60.9 HCl(aq) 56.5 H2(g) 130.58 Zn2+ (aq) -106.5 cl(aq) 55.10 Answer: Check
please help Zinc reacts with hydrochloric acid according to the reaction equation Zn(s) +2HCl(aq) ? ZnCl2(aq)-H2(g How many milliliters of 4.50 M HCl(aq) are required to react with 5.25 g of an ore containing 50.0% Zn(s) by mass? Number mL
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 6.50 M HCl(aq) are required to react with 4.45 g of an ore containing 39.0 % Zn(s) by mass?
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 4.00 M HCl(aq) are required to react with 7.15 g of an ore containing 43.0 % Zn(s) by mass?
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 5.50 M HCl(aq) are required to react with 2.95 g of an ore containing 43.0 % Zn(s) by mass?
Zinc reacts with hydrochloric acid according to the reaction equation Zn(s) + 2 HCl(aq) ZnCl2 (aq) + H,(8) How many milliliters of 2.50 M HCl(aq) are required to react with 2.75 g Zn(s)? volume:
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 3.50M HCl(aq) are required to react with 2.65g of an ore containing 41.0% Zn(s) by mas
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 5.00 M HCl(aq) are required to react with 2.65 g of an ore containing 26.0 % Zn(s) by mass? volume: mL