I really need help with this.
determine the area under the standard normal curve that lies to the left of (a) Z= -0.96 (b) Z= 0.31 (c) Z= 1.29 and (d) Z= -0.83
The area to the left of
Z=
Ans:
a)
P(z<-0.96)=normsdist(-0.96)=0.1685
b)
P(z<0.31)=normsdist(0.31)=0.6217
c)
P(z<1.29)=normsdist(1.29)=0.9015
d)
P(z<-0.83)=normsdist(-0.83)=0.2033
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