Question

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Determine the ionic strength. u. for each of the solutions. Assume complete dissociation of each salt and ignore any hydrolysis reactions A solution of 0.00418 M HCI. A solution of 0.00135 M LaBr- A solution of 0.000873 M CaBr, and 0.000635 M Cuci,

Answer 1

+3 [ (+3) 0.00135+ (-1) ²01004059 = 0.00405m Answer. Tonic Strength an Bength and zici, 2. ezici a charge ci Concentration. (Assuming complet dissous I He 0.80418m hice. un – Hot & 0100418 0.00418 m U (1) X 0.0118'M + CU240100G)gm) u= 0.0418 ml (6 0.00135 in LaBrz, Labrz - ha + 335 0.00135m 0 3x 0.00135m M= 0.0081 M (C) solution of 010 00 873m Cabr, of 0.000635 m Cultz [ca2+] = 0.000873m [Cuzg=0.000 635m. (617 = 240.000 635M. [Br J = 2x0.000873m url(+2) 40.000873+ [] }x 2X 0000873 + (+2)80.000635 mm (-1)?x 280.0006359 m - [5.2384103 +3,8181037 The = 4,524X103m /

at room temp. * Ionic activity co-efficient. logſ = – 0.51 2; 21 de as soo (M= 0.1m) – 0.3225 log2 = – 0.51X (2) ²x ot logrsoy - 0.3225 Senz-= 10 trou? = 0.4767 (5) Al3+ (u= 0.010) 8-0.51x(+3)x100 % TA3P = 0.3487 &- 0.51 x(+3) 280105} È Dysl Qu= 0.05 m) Popo 10%, = 10-1026.35 - оточ Noista oloqui S-0.51 X (+1) 2 x Joioul (d) Corner) No (u- ooolin) 8. = 10 10-0.01613 J Ir = 0.9635

2+ u= 0.0104m Song 2+ = 10 0.51 x(+22 10.0104 = 10-0.2080 Sing= 0.61944) * PO² u = 0.08 57m) 2,-0.51*(-3)310.0857 - 10 Spor - 161.3437 Por = 0.04531
Ionic strength and ionic activity coefficient depends on charge and concentration of ionic species.