Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 2.0×109 electrons from one disk to the other causes the electric field strength between them to be 1.3×105 N/C .
What are the diameters of the disks?
Given,
N = 2 x 10^9 ; E = 1.3 x 10^5 N/C
We know that
C = e0 A/d
E = V/d => V = E d
Q = CV
Q = e0 A/d x Ed
Q = e0 A E = e0 pi d^2/4
solving for D
D^2 = 4 Q/(pi e0 E)
D = sqrt (4 Q/(pi e0 E))
D = sqrt [4 x 2 x 10^9 x 1.6 x 10^-19/(3.14 x 8.85 x 10^-12 x 1.3 x 10^5)] = 0.0188 m
Hence, D = 0.0188 m = 1.88 cm
Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 2.0×109 electrons from one disk...
Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 2.2×109 electrons from one disk to the other causes the electric field strength between them to be 1.3×105 N/C . What are the diameters of the disks?
Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 2.9×109 electrons from one disk to the other causes the electric field strength between them to be 2.0×105 N/C. What are the diameters of the disks?
Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 1.3×109 electrons from one disk to the other causes the electric field strength between them to be 1.8×105 N/C . Part A What are the diameters of the disks? Express your answer with the appropriate units
Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 2.3×109 electrons from one disk to the other causes the electric field strength between them to be 1.7×105 N/C . What are the diameters of the disks?
Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 2.3×109 electrons from one disk to the other causes the electric field strength between them to be 1.5×105 N/C .
Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 1.9×10^9 electrons from one disk to the other causes the electric field strength between them to be 1.1×10^5 N/C . What are the diameters of the disks?
Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 2.1x10 electrons from one disk to the other causes the electric field strength between them to be 2.010 N/C
Two circular disks spaced 0.50 mm apart form a parallel-plate capacitor. Transferring 1.70 ×10 electrons from one disk to the other causes the electric field strength to be 4.00 ×10^5N/C What are the diameters of the disks?
please answer!
<Ch20 Electric Fields and Forces-2 Item 7 Review | Constants Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 2.5x10 electrons from one disk to the other causes the electric field strength between them to be 1.6x105 N/C Part A What are the diameters of the disks? Express your answer with the appropriate units. HA Du Value Units Submit Request Answer Provide Feedback
Two 2.4-cm-diameter-disks spaced 2.0 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.1×105 V/m . A. What is the voltage across the capacitor? B. How much charge is on each disk? (in C) C. An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.3×107 m/s . What was the electron's speed as it left the negative plate?