Approach used:- here we use the formulae for different properties for wave motion on a string as shown below,
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The equation of a transverse wave traveling on a string is given by y - A...
The equation of a transverse wave traveling on a string is given by y A sin(kx - cot). Data: A-22 mm, k-13 rad/m, - 240 rad/s. What is the amplitude? Submit Answer Tries 0/99 What is the frequency? Submit Answer Tries 0/99 What is the wave velocity? Submit Answer Tries 0/99 What is the wavelen Submit Answer Tries 0/99 For the same wave, find the maximum transverse speed of a particle in the string. Submit Answer Tries 0/99
The equation of a transverse wave traveling on a string is given by y = A sin(kx - ωt) . Data: A=11 mm, k=35 rad/m, ω= 500 rad/s. 1) What is the amplitude? 2) What is the frequency? 3) What is the wave velocity? 4) What is the wavelength? 5) For the same wave, find the maximum transverse speed of a particle in the string.
The equation of a transverse wave traveling in a string is given by y = A sin(kx-at). The tension in the string is 18.0 N, A What is the wave speed? 1 mm, k = 26 rad/m, ω 745 rad/s Submit Answer Tries 0/99 What is the linear density of the string. Submit Answer Tries 0/99
The equation of a transverse wave traveling in a string is given by y-A sin(kx-at). The tension in the string is 18.0 N, A-1 mm, k = 26 rad/m, ω = 745 rad/s. What is the wave speed? Submit Answer Tries 0/99 What is the linear density of the string Submit Answer Tries o/99
The equation of a transverse wave traveling along a very long string is y = 3.96 sin(0.0444πx+ 7.89πt), where x and y are expressed in centimeters and t is in seconds. Determine (a) the amplitude, (b) the wavelength, (c) the frequency, (d) the speed, (e) the direction of propagation of the wave and (f) the maximum transverse speed of a particle in the string. (g) What is the transverse displacement at x = 1.05 cm when t = 0.843 s?
The equation of a transverse wave traveling along a very long string is y = 6.28 sin(0.0223πx+ 3.63πt), where x and yare expressed in centimeters and t is in seconds. Determine (a) the amplitude, (b) the wavelength, (c) the frequency, (d) the speed, (e) the direction of propagation of the wave and (f) the maximum transverse speed of a particle in the string. (g) What is the transverse displacement at x = 4.95 cm when t = 0.876 s?
The equation of a transverse wave traveling along a very long string is given by y = 6.1 sin(0.018πx + 3.1πt), where x and y are expressed in centimeters and t is in seconds. Determine the following values. (a) the amplitude cm (b) the wavelength cm (c) the frequency Hz (d) the speed cm/s (e) the direction of propagation of the wave +x−x +y−y (f) the maximum transverse speed of a particle in the string cm/s (g) the transverse displacement at...
The equation of a transverse wave traveling along a very long string is y = 6.93 sin(0.0395x+361), where and are expressed in centimeters and ta in seconds. Determine (a) the amplitude, (b) the wavelength, (c) the frequency. (d) the speed, (e) the direction of propagation of the wave and in the maximum transverse speed of a particle in the string (e) What is the transverse displacement at x4.63 cm whent 0.510 (a) Number Units (b) Number Units (c) Number Units...
A transverse wave is traveling on a string stretched along the horizontal x-axis. The equation for the vertical displacement y is given by y(x,t) = Asin(kx-wt), where A is the amplitude of the wave is much smaller than the wavelength, an individual particle in the string has constant horizontal displacement x but oscillates in the y-direction. The maximum speed of the particle in the y-direction is... Aw A^2w Aw^2 w/k k/w
Chapter 16, Problem 010 The equation of a transverse wave traveling along a very long string is y 6.77 sin(0.0229x 4.31t), where x and y are expressed in centimeters and t is in seconds. Determine (a) the amplitude, (b) the wavelength, (c) the frequency, (d) the speed, (e) the direction of propagation of the wave and (f) the maximum transverse speed of a particle in the string. (g) what is the transverse displacement at x = 2.50 cm when t...