1) amplitude A =22 mm = 22*10-3 m
2) frequency f = /2 = 240/(2) = 38.19 Hz
3) velocity = /k = 240/13 = 18.46 m/s
4) wavelength = 2/k = 2/13 = 0.483 m
5) For a particle undergoing simple hormonic motion , its max speed v = A = 240 * 22*10-3 = 5.28 m/s
The equation of a transverse wave traveling on a string is given by y A sin(kx...
The equation of a transverse wave traveling on a string is given by y - A sin(kx - ot) Data: A-22 mm, k-13 rad/m, 240 rad/s. What is the amplitude? Submit Answer Tries 0/99 What is the frequency? Submit Answer Tries 0/99 What is the wave velocity? Submit Answer Tries 0/99 What is the wavelength? Submit Answer Tries 0/99 For the same wave, find the maximum transverse speed of a particle in the string. Submit Answer Tries 0/99
The equation of a transverse wave traveling in a string is given by y-A sin(kx-at). The tension in the string is 18.0 N, A-1 mm, k = 26 rad/m, ω = 745 rad/s. What is the wave speed? Submit Answer Tries 0/99 What is the linear density of the string Submit Answer Tries o/99
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The equation of a transverse wave traveling in a string is given by y = A sin(kx-at). The tension in the string is 18.0 N, A What is the wave speed? 1 mm, k = 26 rad/m, ω 745 rad/s Submit Answer Tries 0/99 What is the linear density of the string. Submit Answer Tries 0/99
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