8-53.
a.
Moles of HCl = 1.40 mol
Volume of HCl solution = 1.45 L
Molarity = moles of solute/liter of solution
= 1.40 mol/1.45 L
= 0.966 M
b.
Moles of HCl = 0.850 mol
Volume of HCl solution= 0.867 L
Molarity = moles of solute/liter of solution
= 0.850 mol/0.867 L
= 0.980 M
c.
Mass of HCl = 30.0 g
Molar mass of HCl = 36.5 g/mol
Moles of HCl = mass of HCl/molar mass of HCl
= 30.0 g/36.5 g/mol
= 0.822 mol
Moles of HCl = 0.822 mol
Volume of HCl solution= 1.45 L
Molarity = moles of solute/liter of solution
= 0.822 mol/1.45 L
= 0.567 M
d.
Mass of HCl = 30.0 g
Molar mass of HCl = 36.5 g/mol
Moles of HCl = mass of HCl/molar mass of HCl
= 30.0 g/36.5 g/mol
= 0.822 mol
Moles of HCl = 0.822 mol
Volume of HCl solution= 875 mL = 0.875 L ( 1 mL = 0.001 L)
Molarity = moles of solute/liter of solution
= 0.822 mol/0.875 L
= 0.939 M
For each of the following HCl solutions, the moles or grams of solute present and the...
8-47 Calculate the mass-volume percent of MgCl, in each of the following solutions. a. 5.0 g of MgCl, in enough water to give 250 mL of solution b. 85 g of MgCl, in enough water to give 580 mL of solution 8-43 Calculate the volume percent of solute in each of the following solutions. a. 20.0 mL of methyl alcohol in enough water to give 475 mL of solution b. 4.00 mL of bromine in enough carbon tetrachloride to give...
3. Calculate the amount of solute, in moles, grams or milliliters, needed to prepare the following solutions Show all the step by step solution: a. 1.00 L of a 3.00 M NaCl solution (moles of solute) b. 2.00 L of a 1.50 M NaOH solution (grams of solute) c. Milliliters of 1.50 M NaCl solution to obtain 4.78 g of NaCl
Calculate the mass, in grams, of solute present in each of the following solutions. (a) 376 g of 1.25% potassium nitrate solution (b) 115 g of 2.62% sodium chloride solution (c) 1.49 kg of 5.48% ammonium chloride solution (d) 443 mg of 11.1% ammonium nitrate solution
12. Molarity, M, is defined as A. moles of solute dissolved in 1 mol of solvent. B. moles of solute dissolved in 1 kg of solvent. C. moles of solute dissolved in 1 L of solvent. D. moles of solute dissolved in 1 L of solution. E. moles of solute dissolved in the solution. 13. What volume of 2.50 M NaOH (40.00 g/mol) contains 0.100 mole of NaOH? A. 0.250 L D. 0.250 mL B. 40.0 mL E. 0.0400 mL...
How many moles of the indicated solute does each of the following solutions contain? (a) 5.20 mL of 0.147 M CaCl2 solution 40 mol (b) 11.0 mL of 0.416 M NaOH solution mol (c) 1.75 L of 13.0 M HCl solution mol (d) 19.5 mL of 2.80 M NaCl solution mol
2. Calculate the molarity (M) of 30.0 g of NaOH in 350 mL of NaOH solution. Show all the step by step work: 3. Calculate the amount of solute, in moles, grams or milliliters, needed to prepare the following solutions. Show all the step by step solution: a. 1.00 L of a 3.00 M NaCl solution (moles of solute) b. 2.00 L of a 1.50 M NaOH solution (grams of solute) c. Milliliters of 1.50 M NaCl solution to obtain...
How many grams of solute are present in each of these solutions? a. 47.2 mL of 0.351 M HBr g HBr ot b. 103.0 L of 1.21 M Na2 COs pt pt g Na2COs c. 31.7 mL of 6.2 M CH3 COOH g CH3COOH pt d. 2.4 x 10 L of 1.40 M H2SOs 1 pr g H2SO 1 pt 8 item attempts remaining Try Another Version Submit Answer 1 pt 1 pt 1 pt 1 pt 1 pt
For each of the following solutions, the number of moles of solute is given, followed by the total volume of the solution prepared. Calculate the molarity of each solution. (a) 0.630 mol KBr; 125 mL M (b) 0.630 mol KBr; 250. mL (c) 0.630 mol KBr; 500 ml M (d) 0.630 mol KBr; 1.00 L
Calculate the grams of NaOH present in 10.0 mL of a 8.0% (m/v) NaOH solution. 8.0 g 0.80 g 0.72 g 7.2 g Question 8 Which of the following solutions has a molarity of 2.0? 0.020 mole of solute in 50.0 mL of solution 3.0 moles of solute in 3.0 L of solution 0.050 mole of solute in 25.0 mL of solution 2.0 moles of solute in 500.0 mL of solution
Concentrations of solute in solvent, whether in saturated solutions or not, can be expressed in many ways (molarity, molality, ppm, percent by mass, etc.). Molarity = moles of solute / liter of solution molality = moles of solute / kg of solvent ppm = mg solute / liter of solution ppb = microgram of solute / liter of solution %-by-mass = (grams of solute / grams of solution) x 100% To convert from %-by-mass to Molarity, assume 100g of solution,...